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Given Initial concentration c_1 = 9 mu g/mu l final concentration c_2 = 1 mu g/mu l final volume v_2 = 0.1 ml we know v_1 c_1 = v_2 c_2 v_1 = v_2 c_2/c_1 v_1 = 0.1 ml times 1 mu g/mu l/9 mu g/mu l v_1 = 0.0111 ml v_1 = 11.11 mu l final volume v_2 = 0.1 ml = 100 mu l solvent to be added = 100 mu l - 11.11 mu l = 88.89 mu l Take 11.11 mu l of initial solution and add 88.89 mu l of solvent to dilute it.
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