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Balance reaction - Pb(NO₃) + akce Pbcl + 2 KNO3 Cag) lag) (s) cag) I mole Pb(NO₂), require 2 mole kae. So, 0.500 mole Pb(NO3), require kel= 2x0.500 = 1.00 male ke present = 1.50 mole (or excers? so, limoting reagent = .Pb(NO3)2 excess reagent = ke So, moles of Pbch formed a moles of Pb(NO3)2 - De molen so, precipitate pbce formed a noh 0.500 mole 0.500
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