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loco Mole of NaOH = 2 x 0.4 mol =8x10 mol 1. Mole = volleit) & Molarity khem added 50 ml H2O so, total volume = 2m1250ml =520m/ i molarity of NaOH = 88104 = 0.0154M eo mole of New NaOH = 8x10 mol-0088103 mol mole of Hel= 15 408 = 12x103 mol i Remaining THT (12 +0.83x10 mol 11.2x103 mol . molarity of it = 11.2 x 103 (15482) - 1967 -0167M .. pH = -log[w] =-log [o167) = 0.777 PH=0.777
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