## Answers

First one is easy,

you know that x-2 and x-3 must be factors of the quadratic.

let the equation be

y = a(x-2)(x-3)

sub in (4,2) to solve for a, and you are done

the second takes a bit more work.

let the equation be

y = ax^2 + bx + c

now take each point and sub into that, giving you 3 equation in 3 unknowns.

first one:

-2 = a + b + c

take it from there..

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