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: When a 3 kg mass is attached to a spring whose constant is 12 N/m,...

Question:

: When a 3 kg mass is attached to a spring whose constant is 12 N/m, it comes to rest in the equilibrium position. Starting a

: When a 3 kg mass is attached to a spring whose constant is 12 N/m, it comes to rest in the equilibrium position. Starting at i=0, a force equal to f(t) = 15e-54 cos 4t is applied to the system. In the absence of damping, (a) find the position of the mass when t=n. (b) what is the amplitude of vibrations after a very long time?

Answers

Date Page - attached mass cm) = 3 kg spering constant (k) - 12 Nm external force 15e-5t costt then the egn of spring-mass sys

Date Page xact) : a [C, est coset Cz e-st Sinet] a t² 9 Cie 5t Cost + 40 C, est sinat 40 C2 e 5t Cosat +9 Cze-5t Sint so putDato Page total soin will be X(t)= Xicti + ₂ ct) Acos 2t + 8 sinat & 65 e 5t Cosat 1769 200 eest sinut (769 the initial condi

Date Page put the value of A & B in egn 6 so X(t) = -65 bosat + 1125 sinat 1 769 3538 + 65 2-5+ 6054 t 200 e-5t Sin 4t 1769 1

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