Answers
For benzoic acid:
Q=CdT
Q=26380*0.225=5935.5J
5935.5J=C*1.643
C=3612.6
For caffeine:
Q=3612.6*1.564=5650.1
moles=0.260/194=0.0013
Q(KJ/g)=21.73
Q(KJ/mol)=4346.2
.Heat released by benzoic acid:
0.225 g benzoic acid * 26.38 kJ/g = 5.9355 kJ
Heat capacity of the calorimeter:
5.9355 kJ / 1.643 °C = 3.61 kJ/°C
Moles of a 0.265 g sample of caffeine, using molar mass:
0.265 g caffeine / 194.19 g/mol = 0.0013646 moles
Heat released by caffeine
the temperature rises 1.594 °C * 3.61 kJ/ °C = 5.75 kJ
Heat of combustion per mole of caffeine:
5.75 kJ / 0.0013646 moles = 4216.9 kJ/mol