## Answers

pH = pka + dog [NazH POG) and [H₂PO4 PH = 6:55 pka = 7.2 [H3PO4) = 0.23M pH = pka + log In [MazhPou] [H₂PO4] 6:55 = 7.2 + lou (Na2HPO4. [0.23] doo [Na₂Hpoy] = 0.65 dog 17023] dog [Na, 4t P06] – log (0:23) = 0.65 dog [Naz HP04] + 0.638 = 0.65 dog [Naz HP04] = 0.65-0.638 = 0.012 [Muz HPO4) = 4:02M So, molecular mass of Na2HPO4 = 141.95g mail . 141.95 g of [Naz HPO4] is required. Note : нем и Каи Рka vш и 7:2. Becatku Pursh buften system reaction - H3PO, Ht+ H2 pou - t + Hpon ut+pour 1 pk4, 22:2 Pkaz=7.2 p pk az = 1241 Pka = 7-2

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