1 answer

What is the polar form of #( 11,55 )#?

Question:

What is the polar form of #( 11,55 )#?

Answers

Rectangular #(x,y)=(11,55) rarr# Polar: #(r,theta)~~(56.09,78.69^circ)#

Explanation:

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#tan(theta)="opposite"/"adjacent" rarr theta = "arctan"("opposite"/"adjacent")#

#theta = "arctan"(55/11)="arctan"(5)~~1.3734 ("radians) or 78.69^circ#

By Pythagorean Theorem:
#r=sqrt(11^2+55^2)~~56.09#

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