## Answers

d'elee ; T= 300k. Given datai diameter = 20 mm = 2.636 x cohe Alm Current = 700 i k = 0.15 wfm-k. Solution: 1) Rate of heat los by convection per unit length: q=k2R = 700 x 2.636*10% = 129.16 o wlm.

Baunu = 129.16 wlm (Aus) 3) Nusselt number without insulation: Properties of art @ 300 & V = 15.89€ 16.6 mila ik=0.0268 wlmck: Pi= 0.707 Vd Rea= Pvd 20 x 20 x 3 c м 25,173 18.89*600 Using churchel -Bernstein equation, 7 Nugah A R 0.37 0.62 Rey [Reo al oy f 26200 (1 70483%]" = 0.3790.27 - 90.57 Nasselt Number Nas= [90.59 Comas ha 90.57X 0.0263 119.11 whick. 2013 3) Live temperature without insulation. 9 = hA(Foto) & 129.16 = 119,11 XT X20X163 x Et co] I line tempestive, (T= 21.5°C Cams

4) Convection heat transfer coefficient: (amm thook Do = 20th = 24 mm Re va 20 x 24 x 6 3 30,207.67 v 15.89 x wb hD 0.3t 200.68 100.98 ha coord* 0.026? 132.78 w/male 20760-3 Convection heat transfer coefficient 1 89.78 wine e mi 5) Total thermal resistance per unit length: ln (?) anki + (132.78xTx 260 Rotal ln (Tal.) tha. 2h 0.15 0.2932 bitw. 0.1986 t 0.099 = Total thermal resistance = 10.2982 0.2932 km/w) (As) b) Line temperature worth insulation: AT 92 Rrotal, AT= 129.06x 0.2932 AT = 37.88°c) ons Answers: w/mor Stap 1: [129.16 wlm Step 2: (90.57 Step 3: 37.252 Steph: 1182.18 Step 5: (02932] km/u Step 6: 137.8°C

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