Answers
#
Temperature, 
Volume, V = 15 L
Mass of Boron triflouride produced is 34 gm.
Molar mass of boron triflouride = 11+19*3 = 11+57 = 68 gm/mol
Hence, number of moles of BF3 , n = 34 gm/ 68 gm/mol = 0.5 mol
Assuming the gas obeys ideal gas laws,
Where p = pressure, in atm
R = gas constant = 
Putting all the values together,
hence, the pressure of BF3 gas after the reaction is 0.75 atm.
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