## Answers

In case of any doubt please comment below

Solution: (1) we 'anou 2 + 3x² + 7e² +82 +18 32 + 2x+ 2 Using long division method ci 3+2x+2) 2 se'+3x²+ 7%? + +8x+18 ( x + x +3 bet +232 + 2x 2 6 pleatonb t otes + 5 x2 +84 x² + 2x2 + za o + 32? +63 +18 3%? +6x + 6 Ot + 12 ہا Remainder Hene, Remainder 12 quotient 11 sh+ 2+ 3

Solution! (2) ses- 38"-12%? +128-13 x +18 2-5 Using Synthetic division -12 1 2 -13 18 G 5 10 -10 TO -15 1 2 -2 2 -3 3 Remainder = ) quotient - x + 2x² - 2x² - 2x + 2x - 3 Remaindera 3 Solution! 3 we hare f(x1) = 273-78²-8+14 Divide f(x) by (x-4) to get Remainder 4 2 -7 ly -16 - 8 4 2 1 -4 -2 G Remainder Hinu, f(4) -2 Remainder theorem flu) = (Quotient) (divisor) + Remainder It Quotient division is factor of f(x) then Remainder be zero ou

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