1 answer

Torque in a current loop...please help!!!

Question:

17718D.jpgA current Iflows around a plane circular loop of radiusr, giving the loop a magnetic dipole moment of magnitudem.The loop is placed in a uniform magnetic field B_vec, with an angle phi between the direction of the field lines and the magneticdipole moment as shown in thefigure.Find an expression forthe magnitude of the torque tau on the current loop.Express the torque explicitly interms of r,I,pi, phi, and B(where rand Bare the magnitudes of the respective vectorquantities). Do not usem.You will need a trigonomeric function [e.g..sin(phi) or cos(phi)].

Answers

Hopefully this will help u in little bit.........generally torque τ = r x F (cross product)=rF sin φwhere in magnetic field,FB = q (v x B )hence, τB = rFB sin φ= r q v B sin φ= r (It) v Bsinφ(from the definition of current flows, I = Q/t).

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