## Answers

Beer lambert law: The given problem is based on A,=Ecid -i) Az = Elzl - cii) soviding eqh (i) by equ Lii) we get Anal – Cii) where Ai= absorbance = 1:0 Az = asserbance = 0.79 . ; C,= 1.20m ; C2 = ? le deu cases by 21% values in equ liii) we get Plugging the 0.45M C 1.20MX0.79 1.0 A ciri = C₂ V2 1.20m x 20ml =0.95m x ₂ V = 1.20mx20ml 0.95M = 25.3 me ... volume of water added = V₂-v. = 25.3ml - 20.0ml - 5.3 me

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