## Answers

Answer

we have the following data

x | P(x) |

8 | 0.1 |

90 | 0.2 |

125 | 0.5 |

180 | 0.1 |

350 | 0.1 |

First, we need to find the mean

we know mean =

setting the values, we get

Mean=

Now, the formula for standard deviation is given as

setting the given values, we get

on solving, we get

**So, the required standard deviation for this salary distribution is approximately is 83.02 (rounded to 2 decimals)**

r P(z)

μ (8 * 0.1) + (90 * 0.2) + (125 * 0.5) + (180 * 0.1) + (350 * 0.1) = 134.3

We were unable to transcribe this image

νΊδ2 * 0.1) + (902 * 0.2) + (125? * 0.5) + (1802 * 0.1) (3502 * 0.1)]-(134.3)2 σ

σ = V/24928,9| _ 18036.49 = V689241-83.02

.
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