1 answer

The U-238 nucleus emits a 4.2MeV alpha particle . what is the total energy released in this decay

Question:

the U-238 nucleus emits a 4.2MeV alpha particle . what is the total energy released in this decay


Answers

1eV =1.602×10-19 J

4.2 MeV =4.2×106 eV

= 4.2×106×1.602×10-19 J

=6.73 ×10-13 J

Total energy released during this decay is 6.73×10-13 J

.

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