## Answers

The sum of three numbers is 123. The second number is 9 less than two times the first number. The third number is 6 more than three times the first number. Find the three numbers. -------------------------------------- Let the numbers be a,b,c EQUATION: a+b+c=123 b = 2a-9 c = 3a+6 ------------------------ Rearrange the equations: a +b+c = 123 2a-b+0 = 9 3a+0-c = -6 ------------ solve this system of three equations any way you know how.

------------ I get a=21, b=33, c=69 ============================= Cheers, Stan H..

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