1 answer

A. The drawing shows a bar magnet falling through a metal ring. In part a the...

Question:

A. The drawing shows a bar magnet falling through a metal ring. In part a the ring is solid all the way around, but in part b it has been cut through.

S S N N (a) (b)

1. Explain why the motion of the magnet in part a is retarded when the magnet is above the ring and below the ring as well.

2. Draw any induced currents that appear in the ring.

3. Explain why the motion of the magnet is unaffected by the ring in part 2.

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B.

A magnetic field of magnitude B = 0.20 T is reduced to zero in a time interval of Δt = 0.10 s, thereby creating an induced current in a loop of wire. Which one or more of the following choices would cause the same induced current to appear in the same loop of wire?

B = 0.40 T and Δt = 0.20 s
B = 0.30 T and Δt = 0.10 s
B = 0.30 T and Δt = 0.30 s
B = 0.10 T and Δt = 0.050 s
B = 0.50 T and Δt = 0.40 s
S S N N (a) (b)

Answers

© In A the ring, the magnetic field changes (increases). an oppose the paut When the magnet approaches associated with the ripeth ③ in paut la , the ring is cut. 3o the induced current donot have a closed to flowe. so the magnet is unaffected B Let ÀdB = 0.31 ; dt oilS .: I = A x 0.3 - 31/2 > not possible dB = 0.31 ; dt = 0.35 :: I - A х 0.3 0:3 - AR > not possible. dB -0.

.

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