## Answers

a)

Given | |

X bar | 1871 |

S | 590 |

n | 80 |

α= | 0.05 | |

df | 79 | n-1 |

95% CI

CI | ||

tc | 1.99045 | T.INV.2T(alpha,df) |

ME | 131.2981 | tc*(S/SQRT(n)) |

Upper | 2002.298 | X bar + tc*(S/SQRT(n)) |

Lower | 1739.702 | X bar - tc*(S/SQRT(n)) |

a)

Margin of error (ME) = 131 (rounded)

b)

95% CI = (1740, 2002)

c)

Estimate of the total amount

Xbar * n = 1871*80 = $149680

d)

the amount spent on restaurants and carryout food is skewed to the right, the median amount spent to be less than $1871

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