1 answer

T is a real number and P=(square root of 3/2, 1/2) is the point on the unit circle that corresponds

Question:

#sinT=y/r=1/2#

Answers

See explanation.

Explanation:

Given the point #P=(sqrt(3)/2;1/2)# on the angle's side we have:

#x=sqrt(3)/2#, #y=1/2#

#r=sqrt(x^2+y^2)=sqrt(3/4+1/4)=1#

Now we can calculate the trig. functions:

#sinT=y/r=1/2#

#cosT=x/r=sqrt(3)/2#

#tanT=y/x=1/2-:sqrt(3)/2=1/2xx2/sqrt(3)=1/sqrt(3)=sqrt(3)/3#

#cotT=x/y=1/tanT=sqrt(3)#

#secT=r/x=1-:sqrt(3)/2=2/sqrt(3)=(2sqrt(3))/3#

#cscT=r/y=1-:1/2=2#

.

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