1 answer

Suppose the angular velocity of a disk of radius R = 6 cm increases uniformly from...

Question:

Suppose the angular velocity of a disk of radius R = 6 cm increases uniformly from 14 rad/s to 24 rad/s in 0.04 s. What is th
A simple pendulum (mass on a string) oscillates with a period T. The mass is then doubled. The period is now: 0 27 OT/2 OT O
Suppose the angular velocity of a disk of radius R = 6 cm increases uniformly from 14 rad/s to 24 rad/s in 0.04 s. What is the magnitude of the TOTAL acceleration of a point on rim of the disk when the angular velocity is 24 rad/s? O 0.18 m/s2 0 38 m/s2 O 0.15 m/s2 O 35 m/s2 200 m/s2 O 50 m/s2 O 0.72 m/s2 o 15 m/s2 O 3 m/s2
A simple pendulum (mass on a string) oscillates with a period T. The mass is then doubled. The period is now: 0 27 OT/2 OT O T/4 O 4T

Answers

Total acceleration: az ti Translational var}+(ak)? Rotational Quy=aXR = do at XR- 24-14) x 6610-²= (29.00) 0.04 ap = w?R= (24Time period is independent of mass.Hence ,time period will remains same.

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