## Answers

As per given data Z_g = Z_0 = Z_01 = 50 Ohm Z_L1 = 100 + j 0 Ohm Z_L 2 = 0 Ohm d = lambda/2 pi tan^-1 (squareroot Z_L1/ 20) = lambda/2 pi tan^-1 (squareroot 100/ 50) = lambda/2 pi (54.7 degree) d = 0.152 lambda L = lambda/2 pi tan^-1 (squareroot Z_L1 Z_0/Z_L1 - Z_0) = lambda/2 pi tan^-1 (squareroot 100 times 50/100 - 50) = lambda/2 pi (54.7) L = 0.152 lambda

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