## Answers

Given R(x) = 395 x - 0.6 x^2 differentiating R(x) twice in succession w.r.t x, we get R'(x) = 395 - (0.6 times 2)x and R''(x) = -1.2 For maximum or minimum value of R(x), we have R'(x) = 0 Rightarrow 395 - 1.2x = 0 Rightarrow x = 395/1.2 and [R''(x)] = -1.2 < 0 at x = 395/1.2 therefore R(x) has the maximum value at x = 395/1.2 and [R''(x)]_at x = 395/1.2 = -1.2 < 0 Therefore R(x) has the maximum value at x = 395/1.2 and max value is = R(395/1.2) = 395 times 395/1.2 - 0.6 times (395/1.2)^2 = 780125/12 = 65010.416 TiledEqual 65010.42 therefore Req maximum revenue = 65010.42

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