## Answers

Solution;- Griven theet - mass of metal (MM) = 6-579 Temperature of metal (TM) = 105: 70°C mass of water (MW) = 100.09 Temperature of watex (TW) 21:36°C Final Temperatwaef mixtwer (Tu)-24.91°C Cheat gain by wauler 1 9w=MW SWOTW wherer Sw= 4.1345/9c ATW = | Tf-TW) =) (4.91°C-21. Put the value in the equation! => 3.55.C IW = 150gx4.184.J X 3-55€ qw=1485•32J I water absorb = 1485.32J Ans b) Heat lose by metal we know that Hesut gain or absorb by water so metou Hecut lose = 1485.32J Ans. by water = Heat lose by metal Heat JOSE (0) Heat Capacity of metal sample. Temperature difference for metal (ATM) =(Tm- Tf) = 105.70°C – 24.91°C => 80.79 € .. Hecut lose bymetal (9) Heat Capacity of metal (H) = Temperatwa differencelo 1485.32J ME 80.790 TH= 18-38J."(?) Ans! (d) Specfic Hect of metal (s) S = Heat Capactity of meteu mass of metal Sample = 18:38 JiC-1 6.578 = 2.79756Jn 2.79 9.- Is= 2.798Jogoloch Ane:

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