1 answer

Review Part A A single circular loop of radius 0.23 m carries a current of 2.6...

Question:

Review Part A A single circular loop of radius 0.23 m carries a current of 2.6 A in a magnetic field of 0.96 T What is the ma

Review Part A A single circular loop of radius 0.23 m carries a current of 2.6 A in a magnetic field of 0.96 T What is the maximum torque exerted on this loop? Express your answer using two significant figures. N.m Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining

Answers

Solution :-

We know that,

torque on a loop in magnetic field is given by

B*I*A

Now

A=pi*r^2=3.14*0.23*0.23

=0.166 m^2

So Torque=0.96*2.6*.166

Torque = 0.41N-m

.

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