## Answers

Since experiment no. 1 is not given I am solving 2

SOLN 2

moles of Na2C2O4 = molarity * volume = 0.02557*0.1468 = 0.003753 moles

(1L=1000 mL)

From the Balanced equation we know that 2 moles of KMnO4 will require 5 moles of Na2C2O4

hence moles of KMnO4 required = (2/5) * 0.003753 = 0.001501 moles

Molarity = moles / volume in L

M = 0.001501 / 0.03545 = 0.0423 M

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