Answers
Solutions for parts (i)-(iv) are explained below:
5 1893 i) Critical value ; Zoos . Žo:025 ih) p-value İ) qsy.CT 2.5
QUESTION: The mean weight of watermelons found in a garden last year was 15.4 kg. In a sample of 35 watermelons at the same time this year in the same colony, the mean watermelon weight was found to be 14.6 kg. Assume the population standard deviation is 2.5 kg.
(i) At 5% significance level, can we reject the null hypothesis that the mean watermelon weight does not differ from last year?
(ii) What is the test statistics?
(iii) What is the p-value?
(iv) Find the 95% confidence interval for the population mean
(v) Why would the result in (iv) would support the decision made in part (i)
(vi) If we take another sample of size 35, what is the probability that the upper bound of the 95% confidence interval for population mean to be greater than 16kg?
Solutions for parts (i)-(iv) are explained below:
5 1893 i) Critical value ; Zoos . Žo:025 ih) p-value İ) qsy.CT 2.5