![Question 8 0 out of 10 points A 125 Mw coal-burning power plant is 33% efficient when it operates at full load. Given the heat content of the coal used in this power plant 19 million Btu/ton, what is the daily coal consumption in tons? Selected Answer: [None Given] Correct Answer: 1,633 * 1%](https://i.imgur.com/seoA19O.png)
Answers
Efficiency(eta) = W_net/Q_supply W_net = 125 MW eta = 33% or Q_supply = W_net/eta = 125 MW/0.33 = 378.78 MW = 1292.45 times 10^6 Btu/hr coal used = 19 million Btu/ton = 19 times 10^6 Btu/ton coal consumption = Q_supply/coal used = 1292.45 times 10^6/19 times 10^6 Btu/hr/Btu/ton = 68.02 ton/he 1 hr - 68.02 ton 1 day - 24 hr rightarrow 1632.56 ton Therefore 1632.56 ton/day
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