## Answers

Cy cx . Jam 600 AR 81 fy fed TB z gi 2 fz. x, y, 2 component of forces fn = 650 cos 55° Corso = 285.6 N = 650 Cos55 sin 40 = 939.647N f2=650 sinss²=532449N EM=0 = -Ca(3)+Bz3) - Ę (3)+60(3)=0 My = 0 = B₂ (2) + (3) + 60 (2)=0 SM2=0 ) - Cy (1) - G (3) - By (2) - Fx (2) = 0 &fa=0 - AxtCat Fx=0 Ant=-285.6 2 fy to a fy + B + Cy 20 By + y = 239.647 =) Az + B2 =4720449 20 =) EF= Az+Bzf +60-fzi -+ B = 472.449 = -2 ₂ + 2B2=944.898 3 Cx + 262 =-120 = 36 + 2B 2 =420 (n =- 212.979N, B2=259.47N Ax=272.621N, Az = 212.979 N + Cy+2By - 67.737.

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Cy & By = 239,647 --171. PIN, Cys i} By 411.557N

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