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64 loo by x 8 Equation of hyperbola is, 6e-2) CY+3) = 1 We know for the equation (y - 3) = 1 the centre will be (26) vertices will be (ata,B) foci will be (atae, ß) :: e-vitamin - jit lobo VICG Vai 1. The centre coill be (2,-3) ;; The vertices will be (2+8,-3) e. (10,-3) and (-6,- The foci will be (2 #8. 151, -3) de (2 2161, -3) The equation of asymptotes, Y-(-3) = + 10 (x-2) => Y+3 = + (x-2) => 47+12 +(5x-10) le 5X-47 = 22 5x+4y = -2 4
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