1 answer

Question 13 (4 points) Predict the product of this reaction: но* он heat Я он ОН...

Question:

Question 13 (4 points) Predict the product of this reaction: но* он heat Я он ОН о но он ОН
Question 14 (4 points) Why does the reaction below not occur? Nao Nao The acetate ion can never act as a nucleophile Acetate
Question 15 (4 points) Which one of the following compounds would exist in an ENOL form to the greatest extent? H H ° C of H2
Question 16 (4 points) What is the common name of the compound listed below? N-methyl-N-isobutane N-methyl-2-methyl-1-propana
Question 13 (4 points) Predict the product of this reaction: но* он heat Я он ОН о но он ОН
Question 14 (4 points) Why does the reaction below not occur? Nao Nao The acetate ion can never act as a nucleophile Acetate is a weaker base than the ethoxide The ethoxide is stable due to its location on electronegative atom The reactants are less stable than the products
Question 15 (4 points) Which one of the following compounds would exist in an ENOL form to the greatest extent? H H ° C of H2C=0 ºu H OCH3
Question 16 (4 points) What is the common name of the compound listed below? N-methyl-N-isobutane N-methyl-2-methyl-1-propanamine isobutylmethylamine O sec-butylmethylamine

Answers

Solution- (13 thot و مالی . له * It ca OH heat Main Product When 2 carbonyl groups attached to same carbon, the compound is mizobutyl qesues IZ methyl group? common name - isobutyl methyl amine To rect option- IL وقت) cs Scanned with CamScanner

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