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Ans m1 = 12 = 100 44= 38, x₂ = 40 Pooled Rroportion; net x2 P- 38 440 =0.39 nitha Ivo A100 Ô = 1 Ô = 0.61 P = 0.39 Hypothesis Ho: Pi-P2=0 Hii P-P2+0 Ñ u ni - 30 loo = 0.38 Nos 1 X2 H2 = 0,40 loo Test Statistics ir Z= es NCoil) Véo (tutte) - - Do 289 0.38 -0.40 za 0.39x0.61x It 100 N ( loo 12=-0.29 Pevaluer We can find p-value using Ra Rvalue = 2x P[Z<-0-29] >2 *pnorm (-0.29) Cl 0.7718162 P-value 0.7718
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