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Complete solution for question 1 is given below.
Sohition : Given d = 250 mm A a 0.04 m/ 250 c = 52 3 • From figure tan 38 = Ac AC oc 250 . AC = 144.344 mm 6. AB = 288.68 mm * Area of flow x ABxd x 288.68x 250 2 A s 36084.39 mu O AtoB * kletted perimeter P = V AC²4 oc² x 2 p= V 144,342 + 2502 x a P = 577.35 mm
Hydraulic mean depth A 62.5 mm Р ma 0.0625 m A 0.0369 m² * Chezy's equation is given by Q = AC mi 0.04 = 0.0369 x 52 x v 0.0625xi 6.958103 i = 1 in 143.82 :.(Gradient I in 143.82
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