Answers
Suppose a parallel plate capacitor is connected across a cell. Plate of the capacitor connected with positive terminal of the cell well get positive charge stored over it and that with the negative terminal will get negative charge. Means it appears that positive charge has been shifted from positive terminal to the positively charged plate and from negative terminal to negatively charged plate. So obviously some work must have been done which will be stored in the capacitor as its electric field energy.
Dal = dq .V = dq ( 2 ) = q da So total work done to charge it from i to a ir W = dq = £ 1 2 3 4 This work done will get stored in The from of energy in the capacitor, - So Energy U= ac {Q²0} (b). After disconnecting it from the battery charge over the plates will remain a Constant, so uat and using C- & A : - cat hence uad] .. so on moving the plates farther away, as d increases so energy stored 'U' will also hcrease, a