## Answers

A known thermo couple. V_AB = 39.35T + 2.72 times 10^-2 T^2 mu V. VT here corresponds to temperature cordient when 100 degrees C is the gradient then V_AB = 39.35 times 100 + 2.72 times 10^-2 times 100 times 100 = 39.35 times 100 + 2.72 times 100 = (3935 + 272)mu V = 4207 mu V when the top 0 it temp = 105 degrees C & ambient temp = 40 degrees C Delta T = (105 - 40)degrees C Delta T = 65 Then V_AB = 39.35 times Delta T + 2.72 times 10^-2 Delta T^2 = 39.35 times 35 + 2.72 times 10^-2 times 65^2 = 2557.75 + 2.72 times 10^-2 times 652 = 2672.67 mu V \r\n So alarm voltage will be 2672.67 mu V

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