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For part C equation 4-19 is not provided
The electron orbiting around nucleus experience as force given by coulomb's law = kze^2/r^2_n (pointing radically inward) where = radius of nth orbit z = atomic number (number of protons) k = 1/4 phi epsilon_0 = 9 times 10^9 N m^2/c^2 e = charge of electron = 1.6 times 10^- 19 c this force is balanced by centrifugal force mv^2_n/r_n = k z e^2/r_n mv^2_n = k z e^2/r_n now the energy in n^th orbit is E_n = 1/2 mv^2_n - k z e^2/r_n putting mv^2_n from 1 E_n = 1/2 k ze^2/r_n - k ze^2/r_n = -kze^2/2v_n = -k ze^2/2r_0 n^2 {r_n = r_0 n^2 now the transition n rightarrow n - 2 Vertical-bar delta E Vertical-bar = Vertical-bar E_n - 2 - E_n Vertical-bar = + kze^2/2 r_0 [1/(n - 1)^2 - 1/n^2] = + kze^2/2r_0 [n^2 - (n - 1)^2/n^2 (n - 1)^2] = + kze^2/2r_0 [n^2 - n^2 - 1 + 2n/n^2 (n - 1)^2
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