Answers
12 KN Reactions 8 KNIM Cam B Ax Ym Fa=0; Ax=0 A 12 KN 8k Nm I t I a I LING IN um 2m FBA 32KW 28 KN 3Moco, Ayx 6-8x6x3-12x2=0 My = 28 KN (1) Sty=0, Ay- 8x6-12 +By=0 By = 48-412-28 By = 32 KN (1) 6 SFD & BMD SFD x=3.5m V SED man = 32 KN M2 M3 V,=28KN V₂ = 28-8x4 =-4 KN V3=-4-12 = -16 KN V4 =-16-8x2 = -32 KN rew swear force location 10 - IV 4 4 x x = 3.5m from 'Al BMD (Area of SFD] M BAND Mizo M2 -0+ V x x = 28 x 3.5 49 KNM Mman = 49 km
M3 = 49 + V2 x (+1-2) = 49-414-3.5) 48 kNm My = 48 + V2 th x 2 = 48+/- 16-32) x2 > 0 © Location of heutral axis & moment of inestia' Neutral axis (g) 9 = SAS A = 100x2 nor 20000 m² y = 100 = 50mm 10omm yt Az = 56x200 = 10000 mm2 Y = 10 + 20 - 200 mm 2 nomm W000 x 50+/ABOD X200X2 50mm 20000 + 1000OX2 100 mm Soum from top y = 125 mm moment of enesta (I) using parall axis the ora In Scat Ada I - Il + = (IG, + A, dz ? ) + ( IR + And;)2 I = (2,001939 + 20000 (1725-50 250 (20013 I = 9.25810 9.3671 +10000200-125 0(200-125) I ñ 3.083X16 mmy mmy
@ Absolute monimem bendoy Shrews (Oman) Oman Mmon man unt Imen I min = I= 9.25x168 Mman - 49 KN.m = 49X106 N.man Imon = maxim & I - J = 125 mm Yb = 300-125 = 17 Sum Imex = 175 mm (Bottoun) 6 muna 49x160 x 175 Nemme 9.258108 3 loman = 27.811/mpa (Absolute) Absolute maxomem Sloveo stress (mont Vmon Oman zmant I b .b = 56x2 = 100 mm (At neutal axil) Q man = SAJ = 2 [50 x Yb x H ] = 507² Oman = 50x175x175 = 1531250 mm3 Nman = 32 KN = 3200 N
Zmona 32000 x 1531250 9. 2x 108 x 100 N/mm2 3 Erman 1.589/mpa (Absolute)
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