## Answers

Here we have to check independence of two attributes therefore we use chi square test :

Let

A: Wear seat belt

B: death

**Hypothesis is to be tested:**

Attributes A and B are independent.

against

Attributes A and B are dependent.

**Test Statistic:**

** this is chi square with degrees of freedom 1.**

**if number of rows(r)=2, and number of columns=2 then contingency table is,**

A \ B | B1 | B2 | Total |

A1 | a | b | a+b |

A2 | c | d | c+d |

Total | a+c | b+d | N=a+b+c+d |

if we compare this contengency table to given table

A \B | died(B1) | survive(B2) | Total |

wear seat belt (A1) | a=10 | b=50 | a+b=60 |

Dont wear seat belt(A1) | c=20 | d=30 | c+d=50 |

Total | a+c=30 | b+d=80 | N=110 |

therefore test statistic becomes:

............................................test statistic value.

**critical value:**

**Decision Criteria:**

if then reject Ho at % level of significance.

Here

** **therefore we reject Ho at 1% level of significance.

that is we accept H1

means wearing seat belt and death are dependent on each other.

Но

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xi 110* ((10 * 30) – (50 * 20)) (60) (50) (30) (80)

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