Answers
Here we have to check independence of two attributes therefore we use chi square test :
Let
A: Wear seat belt
B: death
Hypothesis is to be tested:
Attributes A and B are independent.
against
Attributes A and B are dependent.
Test Statistic:
this is chi square with degrees of freedom 1.
if number of rows(r)=2, and number of columns=2 then contingency table is,
| A \ B | B1 | B2 | Total |
| A1 | a | b | a+b |
| A2 | c | d | c+d |
| Total | a+c | b+d | N=a+b+c+d |
if we compare this contengency table to given table
| A \B | died(B1) | survive(B2) | Total |
| wear seat belt (A1) | a=10 | b=50 | a+b=60 |
| Dont wear seat belt(A1) | c=20 | d=30 | c+d=50 |
| Total | a+c=30 | b+d=80 | N=110 |
therefore test statistic becomes:
............................................test statistic value.
critical value:
Decision Criteria:
if 
then reject Ho at 
% level of significance.
Here
therefore we reject Ho at 1% level of significance.
that is we accept H1
means wearing seat belt and death are dependent on each other.
Но
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xi 110* ((10 * 30) – (50 * 20)) (60) (50) (30) (80)
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