Answers
There are 6 feed suppliments on the growth of chickens
The weights are considered for all 6 feeds that is treatments.
a) Using the box plot,
1. The samples taken for each suppliment are simple random samples.
2. The samples taken for each suppliment are independent on each other that is each feed type is independent on each other.
3. The populations from which the samples of feed are selected are normal.
4. The variances of the populations from which the samples are selected are equal.
b) 4 Steps of hypothesis
1.
The null and alternative hypothesis
H0: The means for all levels are equal
H1: Atleat one mean differ from the others.
2. The test statistics
Uisng the software output, the F test statistics is
F value = 15.365
3. P-value
Uisng the output,
P-value = 5.9364e-10 = 0.00000000059364
4. Decision and conclusion
Alpha is not given so it should be 0.05
If P-value > alpha then fail to reject the null hypothesis otherwise reject the null hypothesis
P-value (0.00000000059364) is less than alpha 0.05 so reject the null hypothesis.
Conclusion: Reject the null hypothesis, there is sufficient evidence to support that claim that at least one mean differs across feed type.
c) P-value
P-value is a probability of getting a value of test statistics as more as extreme than the value of test statistics computed from the data, under the assumption that the null hypothesis it true.
P-value is the smallest level of significance which lead to reject the null hypothesis.
That is if the p-value is too small then null would be rejected and if not then it would be fail to rejected.
In this case p-value is too small so it leads to reject the null hypothesis.
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