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FBD 8KN 3 kN/m را جا B am Icy 2m Oa=tant 115 15 361870 Oi= tant 3 = 361870 02 AX TAY equilibrium E Fx=0 Fy=0 EMAFO 115 cx-ucy equations Ax + (y + 8 sin36.87° = 0 Ay. tay - 860536:87°–3x2=0 8x2 +3X2 X (2+1) – Gy x 4 + 4X X 1.5=0 -34 KN E mb=o in Be 3 X2X1 - 2 x Cy-0 cy= 3kN (1) Cy=-14167 KN () Ay = 3x2 +88018-3 Ay = giukN (1) -88016 H4.67 SKN ✓ Ax= 30 Axe +9.867 KN ) 14.667KN B 3 knim B FBD 141667 KN 2m 14.667 KN 3kN '3KN А 91867kN] gilkn

13 KN FBD of AB & kn 13.534 KN 141667kN 8-116 =614 9.867 Sin6361870 -5.92 KN 9.867 kn (361870 36.87° guka 31466536870 =7152 KN 9,867 00536870 tgiu sin361870 = 13.534 KN awal force diagram 14.667KN Shear force diagram 3 KN Im С 131534 KN El 'C B ve = compression the tension B M1917 "YkN 3 3 kN + the upward maneut diagram Montsil = 1X EX & t 1,6X2 = 3:2 kN-m (В + tre Sagging

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