Answers
part A)
concentration of H+ in HBr = 0.105 M
concentration of H+ in HCHO2 = sqrt (Ka x C)
= sqrt (1.8 x 10^-4 x 0.150)
= 5.196 x 10^-3
total [H+] = 0.110 M
pH = -log [H+] = -log (0.110)
pH = 0.958
part B)
in HNO2 , [H+] = sqrt (5.6 x 10^-4 x 0.130) = 8.53 x10^-3 M
[H+] , in HNO3 = 9 x 10^-2 M
[H+] = 0.0985 M
pH = 1.006
part C :
[H+] = sqrt (Ka1 C1 + Ka2 C2)
= sqrt (1.8 x 10^-4 x 0.190 + 1.8 x 10^-5 x 0.23)
[H+] = 6.19 x 10^-3
pH = 2.208
part D)
pH = 3.046
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