2 answers

PH using activities

Question:

Using activities, calculate the pH of a solution containing 0.018 M NaOH plus 0.0120 M LiNO3.
Please show me how you arrived at your answer.

Answers

As defined pH is -log [Hydrogen ion concentration]. For alkali it will be 14 -log[OH ion concentration]) . This relationship is true for dilute solutionsonly. You have 0.013 M NaOH and 0.012 M LiNO3. LiNO3 is a salt and is supposed to be neutral.

Therefore pH of the mixture will mainly depend uponNaOH.
Here pH = 14 (-log[0.013])
= 14 - (-[-2.1139])
= 14 - (1.886)
= 12.114
pH will be 12.1.

PH is -log [Hydrogen ion concentration]. For alkali it will be 14 -log[OH ion concentration]) . This relationship is true for dilute solutions only. Youhave 0.013 M NaOH and 0.012 M LiNO3. LiNO3 is a salt and is supposed to be neutral.

Therefore pH of the mixture will mainly depend upon NaOH.
Here pH = 14 (-log[0.013])
= 14 - (1.744)
= 13.256
pH will be 13.3.

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