Answers
Dear,
a) If the total number of frames in the main memory are 64and the size of each frame is 64 bits then what will be the size ofmain memory inbytes?
Number of frames in main memory = 64
size of each frame =64bits
Size of main memory(in bytes)=number of frames * size of each frame
=64* 8 = 512 bytes
b) Calculate the size of the page table (in bytes) if there are8 pages and there are 256 frames in the main memory? (assuming thatpage table justcontain the information of |f|+|d|)
Sizeof page table = ?
# of pages = 8 = 23
pagetable entry sizeis 3 bytes
# of frames = 256
page tablesize = # of frames * PTE = 256 * 3 =768bytes
c) If 8 bits are used to representthe page number, what will be number of pages in the logicaladdress space of a process?
page number requires to represent = 2^3 = 8 bits
numberof pages requirestorepresent =2^3 * 2^10 =2^13 =13 bytes.
I hope this will helps you!!!!!!!!!!
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