## Answers

For concentration cell, cathode and anode are same electrode

So, Eo = 0

Number of electron being transferred in balanced reaction is 1

So, n = 1

If E is positive anode will be the one with lower concentration

use:

E = Eo - (2.303*RT/nF) log {[Na+] at anode/[Na+]at cathode}

Here:

2.303*R*T/F

= 2.303*8.314*298.0/96500

= 0.0591

So, above expression becomes:

E = Eo - (0.0591/n) log {[Na+] at anode/[Na+]at cathode}

E = 0 - (0.0591/1) log (0.033/0.138)

E = 3.674*10^-2 V

= 36.7 mV

Answer: 36.7 mV

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