moles of NaOh utilized???and finding moles of h-+ neautralized We were unable to transcribe this imageular Anpro Run 2) Laboratory Mar Chemistry A M 10. Volume utilized (final – Initia) Run 2) - mol Run 3) Moles of NaOH tized Run 1). Run 3). Mesles of neutralized by antacid (moles HCI-moles NaOH) Run 2) _mol mol mol Run 1) Run 3) molig Run 2) 13. Moles of H neutralized per gram antacid 81 molig Run 1) mol/g Run 3) Run 2) 0-30800 Run 2)_0.00 _ML malg 14. Average moles per gram antacid #1 15. Mass of antacid #2 Run 1)_0.2938 Run 3)_ 0.3062, Original volume of HCl solution in buret Run 1) 0.00 mL Run 3)_14.90 mL 17. Final volume of HCl solution in buret Run 1)_31:30 ML Run 3) _ 46.90 mL Run 2) 32.70 mL 18. Volume utilized (final – Initial) Run 2) - mL Run 1) Run 3) mL 19. Moles of HCl utilized Run 1) Run 3) Run 2) - mol _mol uffer Capacity of Antacids 265 mL Determining the Buffer Capacity of Anta 20. Original volume Run 2)_4-20 mL Run 2) 4.85 sinal volume of NaOH solution in buret Run 1)_3.35 Run 3)_4.85 mL 21. Final volume of NaOH solution in buret Run 1) 4.20 mL Run 3) 95.70 ml 22. Volume utilized (final - initial) Run 2) - Run 1) Run 3) mL 23. Moles of NaOH utilized Run 2) Run 1) mol Run 3) mol 24. Moles of H* neutralized by antacid (moles HCI-moles NaOH) Run 1) mol Run 2) Run 3). mol 5. Moles of H* neutralized per gram antacid #2 Run 1). mol/g Run 2). Run 3). mol/g Average moles per gram antacid #2 mol/g Cous

He o.1 (M) 2. NAOH 01(M) 3. Mass of antacid Run) 0.3875g Run 2) 0.30268 Run 3) 0.29898 4. Atginal theme of the Run1) 2.15ml Run 2) o.oom Run 3) 0.00ml 5. final roure of ha Ren 1) 51.75 ml Rem 2) 50.00ml Run 3) 49.4 ml 6.Volume untilized l final initial) Ren 1) 49.60 mt Ren 2.) 50.oond Run 3) 49.9ht 7. Moles of Hee utilized bun 1) 4.96 Run2) Ren3) 4.94 8. Original volue of Na Oh Ren 1) 1.00 ml Rina) 1.70 ml Run 3) 2-yond 9. Final roume of wooh fin 1) 1.70ml Run 2) 2.40 ml Run 3) 3.35 ml 10. volume untilized Rusi) 0.70 ml RM2) 0.70 ml Ram3) 0.95 wh 11.Moles of NaOff untilized Ren 1 0.07 Rum2) 0.07 Ram3) 0.095 12. Molees of hot nechalised by antacid (moles of the holes of Nadh) Remi) 4.89 Ren 2) 4.93 Rm3) 4.845 mokes of Het neutralized per grenn antasid #1 Runni) 15.9024 Ram 2) Pets 16-2921 Rm3) kaca 16.2094 16.1346 14. Average moles per gran antacid #1 Ropars dar mol/g volume wilized (final- initial) Rund) 31.30ml Run 2) 32-70ml Rum3) 32 ml 19. Moles of the utilized Run1) 3.13 Run 2) 3.27 Rum3) 3.2 22. Volume utilized (final – initial) Rund) 0.85 ml Run 2) 0.65 ml Run 3) 0.85 ml 23.Moles of NaOH utilized Runs 0.005 Run2) 0.065 Run3) 0.085 24 Moles of Ht neutralized by antacid (moles of HC-moles of NaOH) Rem 1) (3.13-0.085)= 3:045 Run 27/897- 0.065)=3-205 Run 3) (3.2-0.085)= 3.115 25. Mokes of Ht neutralized per gran antacid #2 Rumi 8996 10.36418 Run 2) 10.4058 Run 3) 10.1565 26. Avarage moles per gran antacid #2 10.3088 mol/g .

Moles of NaOh utilized???and finding moles of h-+ nea…

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He o.1 (M) 2. NAOH 01(M) 3. Mass of antacid Run) 0.3875g Run 2) 0.30268 Run 3) 0.29898 4. Atginal theme of the Run1) 2.15ml R

22. Volume utilized (final – initial) Rund) 0.85 ml Run 2) 0.65 ml Run 3) 0.85 ml 23.</p><p>Moles of NaOH utilized Runs 0.005 Run2)

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Moles of NaOh utilized???and finding moles of h-+ neautralized We were unable to transcribe this imageular...

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