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given force - Esê +59 +4K) N. and mass of the particle m= 2.0kg and Initial speed U 4.0mls. let Initial Displacement from initial point is az (2 l + 2h +7êm The magnitude of force is F = √(-5) ²4 (5)² (4)2 = 25+es+16 F = 566 N and magnitude of displacement is dz (2) ²4 (932 (772 Jugtuty - 57 m The acceleration of parchcle is fama az t/m 166 So from from Newtons equation of motion 02 u²+ Las 0² (4) ² + xx 186 xd57 = 16+ 8.12 x 7.54 16+ 61.22 77.22 o 8.78 m/s.

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Particles speed at a =

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