## Answers

with then The expected frequency in Binonnial dixtribution n, Þ parameters in Expected frequency = np. 3) n=130, u=150, Piao.3 Expected frequency = 150 x 0.3= 45 (np) 4) .n=500 Pe=0.9 Then -450 Expected frequency (np) then s n=230 Pt = 6-25 Expected treaman ay = 230 x 0.25 = [57-5 500X0.9 (6) n=415 , Py = 0.08 then Expected frequency = np=41580.08 = 33-2

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