1 answer

I ran an IR and a NMR on the product ethyl (E)- cinnamate. how do I...

Question:

i ran an IR and a NMR on the product ethyl (E)- cinnamate. how do I interpret these results for both.
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....................... 10.009 10.0 X: parts per Million : 1H 7.694 7.654 7512 7,497 7.373 7.368 7.356 7.245 6945 6.914 6.406
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....................... 10.009 10.0 X: parts per Million : 1H 7.694 7.654 7512 7,497 7.373 7.368 7.356 7.245 6945 6.914 6.406 5.945 5916 09 1.166 1.341 1.306

Answers

IR analysis

the band at 1700 cm-1 is due to carbonyl group stretching

the band at 2981 cm-1 is due to aliphatic -CH stretching

the band at 3029 cm-1 is due to aromatic -CH stretching

the band at 3061 cm-1 is due to alkene CH stretching

the band at 1637 cm-1 is due to alkene C=C stretching

the band at 1449 and 1493 cm-1 is due aromatic C=C stretching

the band at around 1195 cm-1 is due to C-O stretching of ester group.

1H NMR analysis

the peak between 7 - 8 ppm is due to aromatic protons

the peak at 6.44 ppm is due to alkene CH proton

the quartet at 4.2 ppm is due to methylene proton of ethyl group

the triplet at 1.3 ppm is due to methyl proton of ethyl group.

.

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