## Answers

This is easy. Lets define the state of the locker as open or closed. At any given point in time we know that a locker will be in one of these two states. Lets say we denote open state by 1 and closed state by 0. so we have to print all the lockers with open state which is 1 at the end of the task.

We can do this in the following way.

Code :

#include <iostream>

using namespace std;

int main() {

//set all lockers state to closed

int lockers[101]={0};

for(int i = 1;i<=100;i++){

//we will start from ith locker for ith student

for(int j=i;j<=100;j=j+i){

//toggle the state of the lockers

lockers[j]=1-lockers[j];

}

}

for(int i =1;i<=100;i++){

if(lockers[i]==1){

cout<<i<<" ";

}

}

cout<<endl;

return 0;

}

**OUTPUT :**

.1 4 9 16 25 36 49 64 81 100

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