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From the law of electromagnetic induction we know, whenever there is a change in magnetic linked with a circuit, there will be inducted emf that is current in the circuit. Let at time t, the rot is at a distance x from some reference point. So magnetic these linked will the rod straightphi = B^rightarrow middot A^rightarrow = B^rightarrow middot lx ri^cap = B l x Magnetic field and area are parallel to each other.
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Therefore induced omt in the circuit Vertical-bar e Vertical-bar = d straightphi/dt = Bl dx/dt = Blv = 0.75 times 0.25 times 5v = 0.9375v 25cm = 0.25m \r\n So the current through the resistance or rod i = e/R = 0.9375/0.25 = 3.75A Due to this current in presence of magnetic field, the rod will experience force F^rightarrow = B^rightarrow times i L^rightarrow = B i L[B^rightarrow uptack i^rightarrow] = 0.75 times 3.75 times 0.25 N = 0.703N
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