of any month?Answers
There are 2 people.
probability that 1st man has his b'day on 5th of jan+feb+march+april+.....+december = 1/31 + 1/30 +1/28 + 1/31 +.....+1/31 = (1/31) x 7 + (1/30) x 4 + 1/28= 169/420
Now, same will be for 2nd man = 169/420
So, probability that both people have b'day on 5th: (169/420)^2
:).
There are 2 people.
probability that 1st man has his b'day on 5th of jan+feb+march+april+.....+december = 1/31 + 1/30 +1/28 + 1/31 +.....+1/31 = (1/31) x 7 + (1/30) x 4 + 1/28= 169/420
Now, same will be for 2nd man = 169/420
So, probability that both people have b'day on 5th: (169/420)^2
.
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